7110 problem

[holubice]

Hi ALLHi ALL
this ?solution? is only for Nokia 7110, if your partial flash not working.

1. backup your 7110 full flash (00200000 - 00600000)!!!
2. copy of backup open in any HEX editor
3. find HEX string "46 82 79 38" (must be on adr. of partial flash range)
4.above this string is byte "46 56 46 ...." and above this is "xx yy 00 16 x2 y2 00 16 .... you see:

.. .. xx yy 00 16 x2 y2
.. .. 46 56 46 .. .. ..
.. .. 46 82 79 39 .. ..

5. you crib byte xx, yy, x2, y2, x3, y3 - WHERE IS x3 and y3 ?!?! is on adr. of xx + (plus) 798h - (if xx is on adr. 003AC1D2 then x3 is on adr. 003AC96A) - !!! adr. 00200000 (Nokia offset) = adr. 00000000 (HEX editor) !!!
6. MUST !!! xx = x3 and yy = y3 !!! MUST
7. now calc. yy + y2 + y3 and note result (CHS)
8. calc. y2 - 1 and with this number rewrite yy and y3
9. for new y2 calc CHS - new(yy + y3)
10. upload back to phone

example of N7110 v 4.88

find "46 82 79 38"
see

1AC1D0 00 16 14 34 00 16 14 2C .. ..
1AC1E0 46 4D 46 56 46 5F .. .. .. ..
1AC1F0 1C 0E 46 82 79 38 .. .. ..
......
1AC960 .. .. .. .. .. .. .. .. .. .. 14 34

xx=14, yy=34
x2=14, y2=2C
x3=14, y3=34

34+2C+34=94
2C-1=2B

new:
yy=2B
y3=2B
y2=94-(2B+2B) =94-56 =3E
y2=3E

you write:

1AC1D0 00 16 14 2B 00 16 14 3E .. ..
1AC1E0 46 4D 46 56 46 5F .. .. .. ..
1AC1F0 1C 0E 46 82 79 38 .. .. ..
......
1AC960 .. .. .. .. .. .. .. .. .. .. 14 2B

IF THIS NOT WORKING YOU MAKE CONTRARY !

CHS=(yy+y2+y3)
yy+1 , write instead of y2
(CHS-new y2)/2=yy (y3)

SORRY FOR MY ENGLISH, you learn Czech language, or write to Martin Knezovic (author of Czech-English dictionary)
BYE

[holubice]

Sorry, sorry, sorry !

This ?solution? you aplicate on "NOT WORKING PARTIAL FLASH" - NO on your phone flash backup !!!

BYE