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02-19-2009, 04:50 | #1 (permalink) |
No Life Poster Join Date: Mar 2007 Location: IN FRONT OF YOU Age: 44
Posts: 1,403
Member: 475440 Status: Offline Sonork: 1604067 Thanks Meter: 965 | How to use and how to flash chaina mobiles with spider man i am just new I will Bi very thank full to you all Asghar Hussain |
02-19-2009, 06:04 | #2 (permalink) |
Freak Poster Join Date: May 2007 Location: Inspire Mobile Age: 43
Posts: 263
Member: 502527 Status: Offline Sonork: 100.1580353 Thanks Meter: 114 | Find Rx .tx Signles easyyy HOW TO FIND RX .TX SIGNLES . It is tasted and also you can test it. 1 step is, we need to find GND from phone. 2 step is, we should power on phone (operation with dead phone: phone must be 100% dead by software)and take multimater put it to voltage. 3 multimeter (-) line put it GND and with (+) line check each connectors , and usually Tx= 1.8v or 2.8v and Rx=1.7v or 2.7v (it will be change by processor but strongly 1.7v or 2.8v not 3v or 4v) This way is too easy and you will save a more time. For example! You have got new brand China miracle phone with USB cable. It has got 12 pin. You must find (Infinity team give good Idea 1.2.3 punkts): 1) GND usually it has got 2 GND. (now we have got 10 pins) 2) We will uncheck USB + and USB- (VSS) just with checking by USB cable (now we have 8 pins) 3) By USB cable we also uncheck V bat+, ac adaptor + polarization (now we have 7 pins) 4) Now from this 7 pins you will find 1 or 3 not used pins (last operation we have 3 or 6 pins to find Rx Tx signals) 5) Now at last operation you should use good multimeter just to find Rx Tx with 1.7v-2.7v or 1.8v-2.8v 6) WHEN PHONE IS POWERD OFF TX AND GND WITH MULTIMETER MAKING BEEEEEP (DIOD TEST OPERATION), WHEN PHONE POWERED ON IT WILL SHOW LIKE DIOD RESISTANS 600-700 OHM BETWIN TX AND GND. I think I have give for every body more information’s. Just try to find. If you find 2-3 phone signals and you will be profi mobile Tx and Rx signals finder. Some times you will not find with this method some phones, but why we have forum? I'm not saying it is 100% solution but I'm saying it is TESTED solution. |
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