To calculate SPKC in zte phones as x760, etc

[elcapitel]

try this:
reset your phone with
mobile on without sim
###825*09#
then insert nck code

br
elcapitel

Originally Posted by azad73

could you plz tell me how to put the nck and spck in to the mobile ? i have them but how to treat?
thanks

[ovlajko]

please anyone can you give me unlock codes for zte s320?
thanx in advace
imei:351629040126527
s/n:321802495053
and
351629040214828
s/n:322903080222
and
351629040220627
s/n:322903110202
from telenor network....
thanx

[suppa]

Originally Posted by elcapitel

..:: For educational purpose ::..

I know how to calculate the SPCK in the ZTE cell following:
SFR 232, SFR 341, SFR 342, ORANGE Vegas, VODAFONE INDIE, X760, X761, X960, GX760, GX761, T-Mobile Vairy Touch.


To calculate the SPCK in this cell, you take digits of IMEI number from 4 digit to 15.
The digits are reversed, put the remaining 12 digits and below the 12 digits of NCK. Then we sum digit by digit, and if it is greater than 10, put the digits on the right and BINGO!
as i show, any examples:
:::::::::::::::::::::::::::::::::::::::::::::::::: :::::::::::::::::::::::::::::::::
-------------------------------
imei : 356 318020000001

reversed 12d: 100000020813
NCK Code : 938950060489
SPCK Code : 038950080292


100000020813 reversed 12 latest imei digits (318020000001)
938950060489 NCK code
038950080292 SPCK code
--------------------------------
--------------------------------
Phone Imei : 357 873022388655

NCK Code : 277338726619
SPCK Code : 723111946987


556883220378
277338726619 : NCK code
723111946987 : SPCK code
--------------------------------
--------------------------------
Phone Imei : 356 318024364560

NCK Code : 284172888404
SPCK Code : 249535208217

065463420813
284172888404 : NCK Code
249535208217 : SPCK Code
--------------------------------


Note: This algorithm was obtained by my Based on comparison of results of NCK and SPCK posts, do not in any other way...



To calculate the NCK all part of: 688950000000 and the respective algorithm...


Best Regards
elcapitel

can you give a unlock code for following zte usb modem
Found modem : MF100
Model : ZTE MF100
IMEI : 353164042500865
Firmware : BD_P671A1V1.0.3B21
Compile date / time : Jul 02 2010 19:21:49
Chipset : Qualcomm MSM6246
SIM Lock status : Locked (Card Lock)

it will ask a 16 digit unlock code.
please help me.
it is a great help for me.
Thanks
Have a Nice day

[elcapitel]

Hi bro
This algo not supported zte usb modem

br
elcapitel

Originally Posted by suppa

can you give a unlock code for following zte usb modem
Found modem : MF100
Model : ZTE MF100
IMEI : 353164042500865
Firmware : BD_P671A1V1.0.3B21
Compile date / time : Jul 02 2010 19:21:49
Chipset : Qualcomm MSM6246
SIM Lock status : Locked (Card Lock)

it will ask a 16 digit unlock code.
please help me.
it is a great help for me.
Thanks
Have a Nice day

[elcapitel]

Hello bro, u need use dc-unlocker or "huawei factory code" imei service.

unlock from this huawei not is for free

br
elcapitel

Originally Posted by sarasin

Hi! Could anyone calculate NCK for HUAWEI U1280 plz?
IMEI 35529103197637-2-25

[sarasin]

Originally Posted by elcapitel

Hello bro, u need use dc-unlocker or "huawei factory code" imei service.

unlock from this huawei not is for free

br
elcapitel

I've no credits for dc-unlocker and i can't buy credits. Is there any other way to solve my problem?

[mchizan]

Thanks to elcapitel ,i have followed this thread and i've learnt alot on unlock codes.'

[mchizan]

And to add on that i managed to write the code in python! its a bit dirty but does the job anyway

Thanks again elcapitel and co.

[elcapitel]

check here:

import hashlib, getopt, sys

magic = [6, 8, 8, 9, 5, 0, 0, 0, 0, 0, 0, 0]

def info():
print "zte-unlock.py: calculates unlock codes for ZTE devices"
print "Based on the reverse engineering of elcapitel and y3kt"
print "Copyright (c) 2010 dogbert <[email protected]>"
print ""

def usage():
print "Options: -i*, --imei=* IMEI of the device"
print ""
print "Example: zte-unlock.py --imei=351234567891239"
print ""

def testIME******sum(digits):
_sum = 0
alt = False
for d in reversed(digits):
assert 0 <= d <= 9
if alt:
d *= 2
if d > 9:
d -= 9
_sum += d
alt = not alt
return (_sum % 10) == 0

def checkIMEI(imei):
digits = []
if len(imei) != 15:
print "IMEI too short/long"
return False
for i in imei:
digits.append(int(i))
if not testIME******sum(digits):
print "IMEI checksum invalid"
return False
return True

def getCode(imei):
digits = []
nck = ""
spck = ""
crosssum = 0
for i in imei[3:15]:
digits.append(int(i))
for i in digits:
crosssum += i
for i in range(0,len(digits)):
code = (digits[i]*crosssum + digits[11-i]*8 + magic[i]) % 10
nck += "%d" % code
spck += "%d" % ((code + digits[11-i]) % 10)
return (nck, spck)

def main():
info()
try:
opts, args = getopt.getopt(sys.argv[1:], "hi:", ["help", "imei="])
except getopt.GetoptError, err:
print str(err) # will print something like "option -a not recognized"
usage()
sys.exit(2)

imei = ""
interactive = False

for o, a in opts:
if o in ("-i", "--imei"):
imei = a
elif o in ("-h", "--help"):
usage()
sys.exit()

if imei == "":
imei = raw_input("Please enter the IMEI of the device: ")
interactive = True

if checkIMEI(imei):
nck, spck = getCode(imei)
print ""
print "Network Control Key (NCK): " + nck
print "Service Provider Control Key (SPCK): " + spck
print "done."

if interactive:
raw_input()

if __name__ == "__main__":
main()

br
elcapitel

Originally Posted by mchizan

And to add on that i managed to write the code in python! its a bit dirty but does the job anyway

Thanks again elcapitel and co.

[mchizan]

Originally Posted by elcapitel

check here:


br
elcapitel

Thanks elcapitel as i said,i tried the your algorithm with python which i am currently learning, i am looking at your code currently,
i saw importing hashlib, was it necessary,?
btw i have attached my code too and i am looking for feedback

writen by mchizan
#Thanks to elcapitel and friends...
magic='688950000000'
def shortImei(imei):
imei=imei[3:]
return imei
def sumImei(shortImei):
sumImei=0
for i in shortImei:
sumImei= sumImei+ int(i)
return sumImei
def mod(str1,num1):
line= ''
for i in str1:
d= int(i)*num1
line= line+(str(d))[-1:]
return line
def revImei(s):
sr=''
im=[]
for i in s:
im.append(i)
im.reverse()
for i in im:
sr=sr+i
return mod(sr, 8)
def figs(imei):
a=shortImei(imei)
b= sumImei(a)
c=mod(a,b) # initial code
d=revImei(a)
return c, d
def add(c, d):
y='' #initialize an empty string to hold values
e=magic # magic number to be added
for i in range(len(c)):
x=int(c[i])+int(d[i])+int(e[i])
y=y+str(x)[-1:] #only last digits to be picked
return y # final unlock code
def getcode(imei):
f,d=figs(imei)
nck= add(f, d)
return nck
print getcode('000000002243814') #add imei in the function getcode('imei')
#862374462246

[EgMarvelous]

Thanks for everyone worked on this and really really i like this forum so much .. i made my own huawei calculator and i think ZTE is more easy than huawei.

But i want to ask you if there is any news for ZTE modems that support to unlock by the NCK ?
Thanks.

[mchizan]

asaik,i normally use cable to unlock, anyone with info?

[unknownPT]

What about 16-digits NCK calculation?
I have a lot of examples (IMEI+NCK pairs) if you need it for reverse engineering and understanding how it works. Can provide here or in private as well.